Advertisements
Advertisements
Question
Find the equation of a line whose slope and y-intercept are m = 2, c = -5
Solution
m = 2, c = -5
y = mx + c
⇒ y = 2x - 5
⇒ 2x - y - 5 = 0
⇒ 2x - y = 5
APPEARS IN
RELATED QUESTIONS
Find the equation of the line passing through : (0, 1) and (1, 2)
A(7, −1), B(4, 1) and C(−3, 4) are the vertices of a triangle ABC. Find the equation of a line through the vertex B and the point P in AC; such that AP : CP = 2 : 3.
The line 5x - 3y +1 = 0 divides the join of (2,m) and (7,9) in the ratio 2: 3. Find the value of m.
Find the value of a line parallel to the following line:
`(2"x")/5 + "y"/3` = 2
Find the equation of a line whose slope and y-intercept are m = `(-1)/2`, c = 5
Find the equation of a line passing through (2,5) and making and angle of 30° with the positive direction of the x-axis.
X(4,9), Y(-5,4) and Z(7,-4) are the vertices of a triangle. Find the equation of the altitude of the triangle through X.
Find the equation of a line passing through the intersection of x + 3y = 6 and 2x - 3y = 12 and parallel to the line 5x + 2y = 10
Find the equation of a line passing through the intersection of x + 2y + 1= 0 and 2x - 3y = 12 and perpendicular to the line 2x + 3y = 9
Find the equation of the straight line perpendicular to 5x – 2y = 8 and which passes through the mid-point of the line segment joining (2, 3) and (4, 5).
