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Question
Find the mass of a 3.5 m long lead pipe, if the external diameter of the pipe is 2.4 cm, thickness of the metal is 2 mm and the mass of 1 cm3 of lead is 11.4 grams.
Solution
Length of the pipe (h) = 3.5 cm = 300 cm
External radius of the pipe (R) = \[\frac{2 . 4}{2} = 1 . 2 cm\]
Thickness of pipe = 2 mm
= 0.2 cm
So internal radius of pipe = 1.2 - 0.2
= 1cm
Thus volume of pipe `=pi(R^2 - r^2)h`
`=22/7 xx ((1.2)^2 - 1^2) xx 300`
`=22 xx 50 xx 0.44 cm^3`
`=484 cm^3`
Mass of 1 cm3 pipe is 11.4 gm
Total mass = 4184 × 11.4 = 5517.6 gm = 5.518 kg.
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