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Question
Solution
Slope of line AB = `("y"_2 - "y"_1)/("x"_2 - "x"_1)`
= `(5 + 1)/(-7 - 3) = - 3/5`
Slope of line parallel to AB
= Slope of AB
= `-3/5`
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Solution:
Slope of line = `("y"_2 - "y"_1)/("x"_2 - "x"_1)`
∴ Slope of line AB = `(2 - 1)/(8 - 6) = square` .......(i)
∴ Slope of line BC = `(4 - 2)/(9 - 8) = square` .....(ii)
∴ Slope of line CD = `(3 - 4)/(7 - 9) = square` .....(iii)
∴ Slope of line DA = `(3 - 1)/(7 - 6) = square` .....(iv)
∴ Slope of line AB = `square` ......[From (i) and (iii)]
∴ line AB || line CD
∴ Slope of line BC = `square` ......[From (ii) and (iv)]
∴ line BC || line DA
Both the pairs of opposite sides of the quadrilateral are parallel.
∴ `square`ABCD is a parallelogram.
If the lines kx – y + 4 = 0 and 2y = 6x + 7 are perpendicular to each other, find the value of k.
