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Find the adjoint of the following matrix. [1-12-235-20-1] - Mathematics and Statistics

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Question

Find the adjoint of the following matrix.

`[(1, -1, 2),(-2, 3, 5),(-2, 0, -1)]`

Sum

Solution

Let A = `[(1, -1, 2),(-2, 3, 5),(-2, 0, -1)]`

Now, M11 = `|(3, 5),(0, -1)|` = −3 − 0 = −3

∴ A11 = (−1)1+1(− 3) = −3

M12 = `|(-2, 5),(-2, -1)|` = 2 + 10 = 12

∴ A12 = (−1)1+2(12) = −12

M13 = `|(-2, 3),(-2, 0)|` = 0 + 6 = 6

∴ A13 = (− 1)1+3(6) = 6

M21 = `|(-1,2),(0,-1)|` = 1 − 0 = 1

∴ A21 = (−1)2+1(1) = −1

M22 = `|(1, 2),(-2, -1)|` = −1 + 4 = 3

∴ A22 = (−1)2+2(3) = 3

M23 = `|(1, -1),(-2, 0)|` = 0 − 2 = −2

∴ A23 = (−1)2+3(−2) = 2

M31 = `|(-1, 2),(3, 5)|` = −5 − 6 = −11

∴ A31 = (−1)3+1(−11) = −11

M32 = `|(1, 2),(-2, 5)|` = 5 + 4 = 9

∴ A32 = (−1)3+2(9) = −9

M33 = `|(1, -1),(-2, 3)|` = 3 − 2 = 1

∴ A33 = (−1)3+3(1) = 1

The co-factor matrix = `[("A"_11, "A"_12, "A"_13),("A"_21, "A"_22, "A"_23),("A"_31, "A"_32, "A"_33)]`

∴ adj A = `[(-3, -12, 6),(-1, 3, 2),(-11, -9, 1)]^"T"`

= `[(-3, -1, -11),(-12, 3, -9),(6, 2, 1)]`

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Chapter 2: Matrics - Exercise 2.2 [Page 51]

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