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Find the marginal demand of a commodity where demand is x and price is y. y = x⋅e-x+7 - Mathematics and Statistics

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Question

Find the marginal demand of a commodity where demand is x and price is y.

y = `"x"*"e"^-"x" + 7`

Sum

Solution

y = `"x"*"e"^-"x" + 7`

Differentiating both sides w.r.t.x, we get

`"dy"/"dx" = "d"/"dx"("x"*"e"^-"x" + 7)`

`= "d"/"dx"("x"*"e"^-"x") + "d"/"dx" (7)`

`= "x" * "d"/"dx"("e"^-"x") + "e"^-"x" * "d"/"dx"("x") + 0`

`= "x" * "e"^-"x" * "d"/"dx"(- "x") + "e"^-"x"(1)`

`= "x" * "e"^-"x" (- 1) + "e"^-"x"`

`= "e"^-"x"(- "x" + 1)`

∴ `"dy"/"dx" = (- "x" + 1)/"e"^"x"`

Now, by derivative of inverse function, the marginal demand of a commodity is

`"dx"/"dy" = 1/("dy"/"dx")`, where `("dy"/"dx") ne 0`

i.e. `"dx"/"dy" = 1/((- "x" + 1)/"e"^"x") = "e"^"x"/(1 - "x")`

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Derivatives of Inverse Functions
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Chapter 3: Differentiation - EXERCISE 3.2 [Page 92]

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