Advertisements
Advertisements
Question
Find the mean and the median of: 10,12, 12, 15, 15, 17, 18, 18, 18 and 19
Solution
Given data: 10,12, 12, 15, 15, 17, 18, 18, 18 and 19
Here, number of terms = 10 which is even
∴ Median =`1/2 {"n"/2 "th term" + ("n"/2 + 1)"th term"}`
`= 1/2 {10/2 "th term" + (10/2 + 1) "th term"}`
`= 1/2 {5 "th term" + 6 "th term"}`
`= 1/2 {15 + 17}`
`= 1/2 xx 32 = 16`
∴ Median = 16
Mean = `"Sum of observations"/"Number of observations"`
`= (10 + 12 + 12 + 15 + 15 + 17 + 18 + 18 + 18 + 19)/10`
`= 154/10 = 15.4`
APPEARS IN
RELATED QUESTIONS
Calculate the mean of the distribution given below using the shortcut method.
| Marks | 11-20 | 21-30 | 31-40 | 41-50 | 51-60 | 61-70 | 71-80 |
| No. of students | 2 | 6 | 10 | 12 | 9 | 7 | 4 |
In a school, 100 pupils have heights as tabulate below:
| Height (in cm) | No. of pupils |
| 121 – 130 | 12 |
| 131 – 140 | 16 |
| 141 – 150 | 30 |
| 151 – 160 | 20 |
| 161 – 170 | 14 |
| 171 – 180 | 8 |
Find the median height by drawing an ogive.
Find the mean of first 12 even numbers.
Find the mean of all odd numbers from 5 to 20. Find the new mean when each number is multiplied by 4.
Find the mode of the following:
21, 22, 28, 23, 24, 21 26, 22, 29, 27, 21, 21, 26, 24, 23
Find the median of:
241, 243, 347, 350, 327, 299, 261, 292, 271, 258 and 257
Calculate the median of the following sets of number:
1, 9, 10, 8, 2, 4, 4, 3, 9, 1, 5, 6, 2 and 4.
The median of first ten even natural numbers is ___________
In a given data, arranged in ascending or descending order, the middle most observation is called ______.
An incomplete frequency distribution is given below
| Variate | Frequency |
| 10 – 20 | 12 |
| 20 – 30 | 30 |
| 30 – 40 | ? |
| 40 – 50 | 65 |
| 50 – 60 | 45 |
| 60 – 70 | 25 |
| 70 – 80 | 18 |
| Total | 229 |
Median value is 46, the missing frequency is:
