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Question
Find the number of ways of selecting a team of 3 boys and 2 girls from 6 boys and 4 girls
Solution
There are 6 boys and 4 girls.
∴ the number of ways in which 3 boys and 2 girls can be selected
= 6C3 × 4C2
= `(6!)/(3!3!) xx (4!)/(2!2!)`
= `(6 xx 5 xx 4)/(3 xx 2 xx 1) xx (4 xx 3)/(2 xx 1)`
= 20 × 6
= 120.
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