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Question
Find the trigonometric functions of 225°.
Solution
Angle of measure 225° :
Let m∠XOA = 225°
Its terminal arm (ray OA) intersects the standard unit circle at P(x, y).
Draw seg PM perpendicular to the X-axis.
∴ ΔOMP is a 45° – 45° – 90° triangle.
OP = 1
OM = `1/sqrt(2)"OP"`
= `1/sqrt(2)(1)`
= `1/sqrt(2)`
PM = `1/sqrt(2)"OP"`
= `1/sqrt(2)(1)`
= `1/sqrt(2)`
Since point P lies in the 3rd quadrant,
x < 0, y < 0
∴ x = – OM = `-1/sqrt(2) and y = -"PM" = -1/sqrt(2)`
∴ P ≡ `(-1/sqrt(2), - 1/sqrt(2))`
sin 225° = y = `-1/sqrt(2)`
cos 225° = x = `- 1/sqrt(2)`
tan 225° = `y/x = (-1/sqrt(2))/(-1/sqrt(2))` = 1
cosec 225° = `1/y = 1/(-1/sqrt(2)) = -sqrt(2)`
sec 225° = `1/x = 1/(-1/sqrt(2)) = -sqrt(2)`
cot 225° = `x/y = (-1/sqrt(2))/(-1/sqrt(2))` = 1
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