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![Balbharati solutions for Mathematics and Statistics 1 (Arts and Science) [English] 11 Standard Maharashtra State Board chapter 2 - Trigonometry - 1 Balbharati solutions for Mathematics and Statistics 1 (Arts and Science) [English] 11 Standard Maharashtra State Board chapter 2 - Trigonometry - 1 - Shaalaa.com](/images/mathematics-and-statistics-1-arts-and-science-english-11-standard-maharashtra-state-board_6:e3c01670e36a48e499844fcbaf828475.jpg)
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Solutions for Chapter 2: Trigonometry - 1
Below listed, you can find solutions for Chapter 2 of Maharashtra State Board Balbharati for Mathematics and Statistics 1 (Arts and Science) [English] 11 Standard Maharashtra State Board.
Balbharati solutions for Mathematics and Statistics 1 (Arts and Science) [English] 11 Standard Maharashtra State Board 2 Trigonometry - 1 EXERCISE 2.1 [Pages 21 - 22]
Find the trigonometric function of :
0°
Find the trigonometric function of :
30°
Find the trigonometric function of:
45°
Find the trigonometric function of :
60°
Find the trigonometric function of :
150°
Find the trigonometric functions of :
180°
Find the trigonometric function of :
210°
Find the trigonometric function of :
300°
Find the trigonometric functions of :
330°
Find the trigonometric functions of :
−30°
Find the trigonometric functions of :
−45°
Find the trigonometric functions of :
−60°
Find the trigonometric functions of :
− 90°
Find the trigonometric functions of :
−120°
Find the trigonometric functions of :
−225°
Find the trigonometric functions of :
−240°
Find the trigonometric functions of :
−270°
Find the trigonometric functions of :
−315°
State the signs of tan 380°
State the signs of cot 230°
State the signs of sec 468°
State the signs of cos4c and cos4°. Which of these two functions is greater?
State the quadrant in which θ lies if :
sin θ < 0 and tan θ > 0
State the quadrant in which θ lies if :
cos θ < 0 and tan θ > 0
Evaluate the following:
sin 30° + cos 45° + tan 180°
Evaluate the following :
cosec 45° + cot 45° + tan 0°
Evaluate the following :
sin 30° × cos 45° × tan 360°
Find all trigonometric functions of angle in standard position whose terminal arm passes through point (3, −4).
If cos θ = `12/13`, 0 < θ < `pi/2`, find the value of `(sin^2theta - cos^2theta)/(2sinthetacostheta), 1/(tan^2theta)`
Using tables evaluate the following :
4 cot 45° – sec2 60° + sin 30°
Using tables evaluate the following :
`cos^2 0 + cos^2 pi/6 + cos^2 pi/3 + cos^2 pi/2`
Find the other trigonometric functions:
If cos θ = `-3/5` and 180° < θ < 270°.
Find the other trigonometric functions if sec A = `-25/7` and A lies in the second quadrant.
Find the other trigonometric functions:
If cot x = `3/4`, x lies in the third quadrant.
Find the other trigonometric functions:
If tan x = `(-5)/12`, x lies in the fourth quadrant.
Balbharati solutions for Mathematics and Statistics 1 (Arts and Science) [English] 11 Standard Maharashtra State Board 2 Trigonometry - 1 EXERCISE 2.2 [Page 31]
If 2 sinA = 1 = `sqrt(2)` cosB and `pi/2` < A < `pi`, `(3pi)/2` < B < `2pi`, then find the value of `(tan"A" + tan"B")/(cos"A" - cos"B")`
If `sin"A"/3 = sin"B"/4 = 1/5` and A, B are angles in the second quadrant then prove that 4cosA + 3cosB = – 5.
If tanθ = `1/2`, evaluate `(2sin theta + 3cos theta)/(4cos theta + 3sin theta)`
Eliminate θ from the following:
x = 3secθ , y = 4tanθ
Eliminate θ from the following :
x = 6cosecθ, y = 8cotθ
Eliminate θ from the following :
x = 4cosθ − 5sinθ, y = 4sinθ + 5cosθ
Eliminate θ from the following :
x = 5 + 6cosecθ, y = 3 + 8cotθ
Eliminate θ from the following:
2x = 3 − 4 tan θ, 3y = 5 + 3 sec θ
If 2 sin2θ + 3 sin θ = 0, find the permissible values of cos θ.
If 2cos2θ − 11cosθ + 5 = 0 then find possible values of cosθ.
Find the acute angle θ such that 2 cos2θ = 3 sin θ.
Find the acute angle θ such that 5tan2θ + 3 = 9secθ.
Find sinθ such that 3cosθ + 4sinθ = 4
If cosecθ + cotθ = 5, then evaluate secθ.
If cotθ = `3/4` and π < θ < `(3pi)/2` then find the value of 4cosecθ + 5cosθ.
Find the Cartesian co-ordinates of points whose polar coordinates are :
(3, 90°)
Find the Cartesian co-ordinates of points whose polar coordinates are :
(1,180°)
Find the polar coordinates of points whose cartesian coordinates are:
(5, 5)
Find the polar coordinates of points whose cartesian coordinates are :
`(1, sqrt(3))`
Find the polar co-ordinates of points whose Cartesian co-ordinates are:
(–1, –1)
Find the polar co-ordinates of points whose Cartesian co-ordinates are:
`(- sqrt(3), 1)`
Find the value of `sin (19pi^"c")/3`.
Find the value of :
cos 1140°
Find the values of:
`cot (25pi^"c")/3`
Prove the following identities:
`(1 + tan^2 "A") + (1 + 1/tan^2"A") = 1/(sin^2 "A" - sin^4"A")`
Prove the following identities:
(cos2A – 1) (cot2A + 1) = −1
Prove the following identities:
(sinθ + sec θ)2 + (cosθ + cosec θ)2 = (1 + cosecθ sec θ)2
Prove the following identities:
(1 + cot θ – cosec θ)(1 + tan θ + sec θ) = 2
Prove the following identities:
`tan^3theta/(1 + tan^2theta) + cot^3theta/(1 + cot^2theta` = secθ cosecθ – 2sinθ cosθ
Prove the following identities:
`1/(sectheta + tantheta) - 1/costheta = 1/costheta - 1/(sectheta - tantheta)`
Prove the following identities:
`sintheta/(1 + costheta) + (1 + costheta)/sintheta` = 2cosecθ
Prove the following identity:
`tantheta/(sectheta - 1) = (sectheta + 1)/tantheta`
Prove the following identities:
`cottheta/("cosec" theta - 1) = ("cosec" theta + 1)/cot theta`
Prove the following identities:
(sec A + cos A)(sec A − cos A) = tan2A + sin2A
Prove the following identity:
1 + 3cosec2θ cot2θ + cot6θ = cosec6θ
Prove the following identity:
`(1 - sec theta + tan theta)/(1 + sec theta - tan theta) = (sec theta + tan theta - 1)/(sec theta + tan theta + 1)`
Balbharati solutions for Mathematics and Statistics 1 (Arts and Science) [English] 11 Standard Maharashtra State Board 2 Trigonometry - 1 MISCELLANEOUS EXERCISE - 2 [Pages 32 - 34]
Select the correct option from the given alternatives:
The value of the expression cos1°. cos2°. cos3° … cos179° =
– 1
0
`1/sqrt(2)`
1
Select the correct option from the given alternatives:
`tan"A"/(1 + sec"A") + (1 + sec"A")/tan"A"` is equal to
2cosecA
2secA
2sinA
2cosA
Select the correct option from the given alternatives:
If α is a root of 25cos2θ + 5cosθ – 12 = 0, `pi/2` < α < π, then sin2α is equal to
`-24/25`
`-13/18`
`13/18`
`24/25`
Select the correct option from the given alternatives:
If θ = 60°, then `(1 + tan^2theta)/(2tantheta)` is equal to
`sqrt(3)/2`
`2/sqrt(3)`
`1/sqrt(3)`
`sqrt(3)`
Select the correct option from the given alternatives:
If secθ = m and tanθ = n, then `1/"m"{("m + n") + 1/(("m + n"))}` is equal to
2
mn
2m
2n
Select the correct option from the given alternatives:
If cosecθ + cotθ = `5/2`, then the value of tanθ is
`14/25`
`20/21`
`21/20`
`15/16`
Select the correct option from the given alternatives:
`1 - sin^2theta/(1 + costheta) + (1 + costheta)/sintheta - sintheta/(1 - costheta)` equals
0
1
sin θ
cos θ
Select the correct option from the given alternatives:
If cosecθ − cotθ = q, then the value of cot θ is
`(2"q")/(1 + "q"^2)`
`(2"q")/(1 - "q"^2)`
`(1 - "q"^2)/(2"q")`
`(1 + "q"^2)/(2"q")`
Select the correct option from the given alternatives:
The cotangent of the angles `pi/3, pi/4 and pi/6` are in
A.P.
G.P.
H.P.
Not in progression
Select the correct option from the given alternatives:
The value of tan1°.tan2°tan3°..... tan89° is equal to
– 1
1
`pi/2`
2
Answer the following:
Find the trigonometric functions of :
90°
Find the trigonometric functions of 120°.
Find the trigonometric functions of 225°.
Answer the following:
Find the trigonometric functions of :
240°
Answer the following:
Find the trigonometric functions of :
270°
Answer the following:
Find the trigonometric functions of :
315°
Find the trigonometric functions of :
−120°
Answer the following:
Find the trigonometric functions of :
−150°
Answer the following:
Find the trigonometric functions of :
−180°
Answer the following:
Find the trigonometric functions of :
−210°
Answer the following:
Find the trigonometric functions of :
−300°
Answer the following:
Find the trigonometric functions of :
−330°
Answer the following:
State the signs of cosec 520°
Answer the following:
State the signs of cot 1899°
Answer the following:
State the signs of sin 986°
Answer the following:
State the quadrant in which θ lies if tan θ < 0 and sec θ > 0
Answer the following:
State the quadrant in which θ lies if sin θ < 0 and cos θ < 0
Answer the following:
State the quadrant in which θ lies if sin θ > 0 and tan θ < 0
Answer the following:
Which is greater sin(1856°) or sin(2006°)?
Answer the following:
Which of the following is positive? sin(−310°) or sin(310°)
Answer the following:
Show that 1 − 2sinθ cosθ ≥ 0 for all θ ∈ R.
Answer the following:
Show that tan2θ + cot2θ ≥ 2 for all θ ∈ R
Answer the following:
If sinθ = `(x^2 - y^2)/(x^2 + y^2)` then find the values of cosθ, tanθ in terms of x and y.
Answer the following:
If sec θ = `sqrt(2)` and `(3pi)/2 < theta < 2pi` then evaluate `(1 + tantheta + "cosec"theta)/(1 + cottheta - "cosec"theta)`
Prove the following:
sin2A cos2B + cos2A sin2B + cos2A cos2B + sin2A sin2B = 1
Prove the following:
`((1 + cot theta + tan theta)(sin theta - costheta)) /(sec^3theta - "cosec"^3theta)`= sin2θ cos2θ
Prove the following:
`(tan theta + 1/costheta)^2 + (tan theta - 1/costheta)^2 = 2((1 + sin^2theta)/(1 - sin^2theta))`
Prove the following:
2 sec2θ – sec4θ – 2cosec2θ + cosec4θ = cot4θ – tan4θ
Prove the following:
sin4θ + cos4θ = 1 – 2 sin2θ cos2θ
Prove the following:
2(sin6θ + cos6θ) – 3(sin4θ + cos4θ) + 1 = 0
Prove the following:
cos4θ − sin4θ +1= 2cos2θ
Prove the following:
sin4θ +2sin2θ . cos2θ = 1 − cos4θ
Prove the following:
`(sin^3theta + cos^3theta)/(sintheta + costheta) + (sin^3theta - cos^3theta)/(sintheta - costheta)` = 2
Prove the following:
tan2θ − sin2θ = sin4θ sec2θ
Prove the following:
(sinθ + cosecθ)2 + (cosθ + secθ)2 = tan2θ + cot2θ + 7
Prove the following:
sin8θ − cos8θ = (sin2θ − cos2θ) (1 − 2 sin2θ cos2θ)
Prove the following:
sin6A + cos6A = 1 − 3sin2A + 3 sin4A
Prove the following:
(1 + tanA · tanB)2 + (tanA − tanB)2 = sec2A · sec2B
Prove the following:
`(1 + cot + "cosec" theta)/(1 - cot + "cosec" theta) = ("cosec" theta + cottheta - 1)/(cottheta - "cosec"theta + 1)`
Prove the following:
`(tantheta + sectheta - 1)/(tantheta + sectheta + 1) = tantheta/(sec theta + 1)`
Prove the following:
`("cosec"theta + cottheta - 1)/( "cosec"theta + cot theta + 1) =(1-sintheta)/costheta`
Prove the following:
`("cosec"theta + cottheta + 1)/(cottheta + "cosec" theta - 1) = cottheta/("cosec"theta - 1)`
Solutions for 2: Trigonometry - 1
![Balbharati solutions for Mathematics and Statistics 1 (Arts and Science) [English] 11 Standard Maharashtra State Board chapter 2 - Trigonometry - 1 Balbharati solutions for Mathematics and Statistics 1 (Arts and Science) [English] 11 Standard Maharashtra State Board chapter 2 - Trigonometry - 1 - Shaalaa.com](/images/mathematics-and-statistics-1-arts-and-science-english-11-standard-maharashtra-state-board_6:e3c01670e36a48e499844fcbaf828475.jpg)
Balbharati solutions for Mathematics and Statistics 1 (Arts and Science) [English] 11 Standard Maharashtra State Board chapter 2 - Trigonometry - 1
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Concepts covered in Mathematics and Statistics 1 (Arts and Science) [English] 11 Standard Maharashtra State Board chapter 2 Trigonometry - 1 are Introduction of Trigonometry, Trigonometric Functions with the Help of a Circle, Signs of Trigonometric Functions in Different Quadrants, Range of Cosθ and Sinθ, Trigonometric Functions of Specific Angles, Trigonometric Functions of Negative Angles, Fundamental Identities, Periodicity of Trigonometric Functions, Domain and Range of Trigonometric Functions, Graphs of Trigonometric Functions, Polar Co-ordinate System.
Using Balbharati Mathematics and Statistics 1 (Arts and Science) [English] 11 Standard Maharashtra State Board solutions Trigonometry - 1 exercise by students is an easy way to prepare for the exams, as they involve solutions arranged chapter-wise and also page-wise. The questions involved in Balbharati Solutions are essential questions that can be asked in the final exam. Maximum Maharashtra State Board Mathematics and Statistics 1 (Arts and Science) [English] 11 Standard Maharashtra State Board students prefer Balbharati Textbook Solutions to score more in exams.
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