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Question
Eliminate θ from the following :
x = 5 + 6cosecθ, y = 3 + 8cotθ
Solution
x = 5 + 6cosecθ, y = 3 + 8cotθ
∴ x – 5 = 6cosecθ, y – 3 = 8cotθ
∴ cosecθ = `(x - 5)/6, cot theta = (y - 3)/8`
We know that,
∴ cosec2θ – cot2θ = 1
`((x - 5)/6)^2 - ((y - 3)/8)^2` = 1
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