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Question
Find the value of k for which points P(k, −1), Q(2, 1) and R(4, 5) are collinear.
Solution
Given, points P(k, −1), Q(2, 1) and R(4, 5) are collinear.
∴ Slope of PQ = Slope of QR
∴ `(1 - (-1))/(2 - "k") = (5 - 1)/(4 - 2)`
∴ `2/(2 - "k") = 4/2`
∴ 4 = 4 (2 − k)
∴ 1 = 2 − k
∴ k = 2 − 1 = 1
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