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Tamil Nadu Board of Secondary EducationSSLC (English Medium) Class 10

Find the value of k, if the area of a quadrilateral is 28 sq. units, whose vertices are (– 4, – 2), (– 3, k), (3, – 2) and (2, 3) - Mathematics

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Question

Find the value of k, if the area of a quadrilateral is 28 sq. units, whose vertices are (– 4, – 2), (– 3, k), (3, – 2) and (2, 3)

Sum

Solution

Let the vertices A(– 4, – 2), B(– 3, k), C(3, – 2) and D(2, 3)

Area of the Quadrilateral = 28 sq. units

`1/2[(x_1y_2 + x_2y_3 + x_3y_4 + x_4y_1) - (x_2y_1 + x_3y_2 + x_4y_3 + x_1y_4)]` = 28

`1/2[(-4"k" + 6 + 9 - 4) - (6 + 3"k" - 4 - 12)]` = 28

`1/2[(-4"k" + 11) - (3"k" - 10)]` = 28

– 4k + 11 – 3k + 10 = 56

– 7k + 21 = 56

– 7k = 56 – 21

– 7k = 35

⇒ 7k = – 35

k = `35/7`

= – 5

The value of k = – 5

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Chapter 5: Coordinate Geometry - Exercise 5.1 [Page 212]

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Samacheer Kalvi Mathematics [English] Class 10 SSLC TN Board
Chapter 5 Coordinate Geometry
Exercise 5.1 | Q 6 | Page 212

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