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Question
Find the value of the following:
(3−1 + 4−1 + 5−1)0
Solution
We know from the property of powers that for every natural number a, a−1 = 1/a.
Moreover, a0 is 1 for every natural number a not equal to 0. Then:
\[( 3^{- 1} + 4^{- 1} + 5^{- 1} ) = 1\] `->`(Ignore the expression inside the bracket and use a0= 1 immediately.)
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