Advertisements
Advertisements
Question
Find the zeroes of the quadratic polynomial `f(x) = 6x^2 – 3.`
Solution
To find the zeroes of the quadratic polynomial we will equate f(x) to 0
`∴f(x) = 0`
`⇒ 6x^2 – 3 = 0`
`⇒ 3(2x^2 – 1) = 0`
`⇒ 2x^2 – 1 = 0`
`⇒2x^2 = 1 `
`⇒x^2=1/2`
`⇒ x=+-1/sqrt2`
Hence, the zeroes of the quadratic polynomial f(x) = `6x^2-3 are 1/sqrt2,-1/sqrt2`
APPEARS IN
RELATED QUESTIONS
Find the zeroes of the polynomial `f(x) = x^2 ˗ 2x ˗ 8` and verify the relation between its zeroes and coefficients
Find all the zeroes of polynomial `(2x^4 – 11x^3 + 7x^2 + 13x – 7)`, it being given that two of its zeroes are `(3 + sqrt2) and (3 – sqrt2)`.
If 1is a zero of the quadratic polynomial `ax^2 – 3(a – 1)x – 1`is 1, then find the value of a.
Write the zeros of the polynomial `f(x) = x^2 – x – 6`.
If the sum of the zeros of the quadratic polynomial `kx^2-3x + 5` is 1 write the value of k..
Find the sum of the zeros and the product of zeros of a quadratic polynomial, are `−1/2` and \ -3 respectively. Write the polynomial.
If one of the zeroes of the cubic polynomial x3 + px² + qx + r is -1, then the product of the other two zeroes is ______.
If f(x) = 5x - 10 is divided by x – `sqrt2`, then the remainder will be ______.
The number of polynomials having zeroes as -2 and 5 is ______.
The number of polynomials having zeroes – 3 and 4 is ______.