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For the given cell, Mg | MgX2+ || CuX2+ | Cu (i) Mg is cathode (ii) Cu is cathode (iii) The cell reaction is MgX+ CuX2+⟶MgX2++Cu (iv) Cu is the oxidising agent - Chemistry

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Question

For the given cell, \[\ce{Mg | Mg^{2+} || Cu^{2+} | Cu}\]

(i) \[\ce{Mg}\] is cathode

(ii) \[\ce{Cu}\] is cathode

(iii) The cell reaction is \[\ce{Mg^+ Cu^{2+} -> Mg^{2+} + Cu}\]

(iv) \[\ce{Cu}\] is the oxidising agent

Short Note

Solution

(ii) \[\ce{Cu}\] is cathode

(iii) The cell reaction is \[\ce{Mg^+ Cu^{2+} -> Mg^{2+} + Cu}\]

Explanation:

(i) Left side of cell reaction represents oxidation half-cell i.e., oxidation of \[\ce{Mg}\] and right side of cell represents reduction half-cell reactions i.e., reduction of copper.

(ii) \[\ce{Cu}\] is reduced and reduction occurs at cathode.

(iii) \[\ce{Mg}\] is oxidized and oxidation occurs at anode.

(iv) Whole cell reaction can be written as

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Chapter 3: Electrochemistry - Exercises [Page 38]

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NCERT Exemplar Chemistry [English] Class 12
Chapter 3 Electrochemistry
Exercises | Q II. 27. | Page 38

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