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For the reaction 3A → 2B, rate of reaction +d[B]dt is equal to ______. - Chemistry

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Question

For the reaction 3A `rightarrow` 2B, rate of reaction `+ (d[B])/(dt)` is equal to ______.

Options

  • `(-3)/2 (d[A])/(dt)`

  • `(-2)/3 (d[A])/(dt)`

  • `(-1)/3 (d[A])/(dt)`

  • `+ (2d[A])/(dt)`

MCQ
Fill in the Blanks

Solution

For the reaction 3A `rightarrow` 2B, rate of reaction `+ (d[B])/(dt)` is equal to `underlinebb((-2)/3 (d[A])/(dt))`.

Explanation:

Rate of reaction = `(-1)/3 (d[A])/(dt) = (+1)/2 (d[B])/(dt)` 

`(dB)/(dt) = (-2)/3 (d[A])/(dt)`

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