Advertisements
Advertisements
Question
How does stopping potential in photoelectric emission vary if the intensity of the incident radiation increases?
Solution
The stopping potential is independent of the intensity of the incident photon.
APPEARS IN
RELATED QUESTIONS
The energy of photon of wavelength X is_____ .
[h = Planck’s constant, c = speed of light in vacuum]
Find the value of energy of electron in eV in the third Bohr orbit of hydrogen atom.
(Rydberg's constant (R) = 1· 097 x 107m - 1,Planck's constant (h) =6·63x10-34 J-s,Velocity of light in air (c) = 3 x 108m/ s.)
Find the wave number of a photon having energy of 2.072 eV
Given : Charge on electron = 1.6 x 10-19 C,
Velocity of light in air = 3 x 108 m/s,
Planck’s constant = 6.63 x 10-34 J-s.
Einstein's photoelectric equation is:
a) `E_"max" = hlambda - varphi_0`
b) `E_"max"= (hc)/lambda varphi_0`
c) `E_"max" = hv + varphi_0`
d) `E_"max" = (hv)/lambda + varphi_0`
With reference to the photoelectric effect, define threshold wavelength
According to the Einstein’s model, stopping potential Vo for a metal having work function ϕ0 is given by ______.
According to Einstein's photoelectric equation, the plot of the kinetic energy of the emitted photoelectrons from a metal Vs the frequency of the incident radiation gives as straight the whose slope:
Who indirectly determined the mass of the electron by measuring the charge of the electrons?
If the frequency of light in a photoelectric experiment is double the stopping potential will
Ultraviolet light is incident on metals P, Q and R, having work functions 8 eV, 2 eV and 4 eV respectively,
- Which metal has lowest threshold frequency for photoelectric effect?
- For which metal is the value of Emax minimum?
(Note: Emax is maximum kinetic energy of the emitted photoelectrons.)
