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Question
Einstein's photoelectric equation is:
a) `E_"max" = hlambda - varphi_0`
b) `E_"max"= (hc)/lambda varphi_0`
c) `E_"max" = hv + varphi_0`
d) `E_"max" = (hv)/lambda + varphi_0`
Solution
`E_"max"= (hc)/lambda varphi_0`
∵ `hv + phi_0 + E_"max"`
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