English
Tamil Nadu Board of Secondary EducationHSC Science Class 12

Identify the type of conic and find centre, foci, vertices, and directrices of the following: (y-2)325+(x+1)216 = 1 - Mathematics

Advertisements
Advertisements

Question

Identify the type of conic and find centre, foci, vertices, and directrices of the following:

`(y - 2)^3/25 + (x + 1)^2/16` = 1

Sum

Solution

It is an hyperbola.

The transverse axis is parallell to y axis.

a2 = 25, b2 = 16

a = ± 5, b = 4

c2 = a2 + b2

= 25 + 16

= 41

c = `sqrt(41)`

ae = `sqrt(41)`

5e = `sqrt(41)`

e = `sqrt(41)/5`

Centre (h, k) = (– 1, 2)

Vertices (h, ± a + k) = (– 1, ± 5 + 2)

= (– 1, 5 + 2) and (– 1, – 5 + 2)

= (– 1, 7) and (– 1, – 3)

Foci (h, ± c + k) = `(- 1 +-  sqrt(41) + 2)`

= `(-1, sqrt(41) + 2)` and `(-1, - sqrt(41) + 2)`

Directrix x = `+-  "a"/"e" + "k"`

= `+-  5/(sqrt(41)/5) + 2`

= `+-  25/sqrt(41) + 2`

y = `25/sqrt(41) + 2` and y = `- 25/sqrt(41) + 2`

shaalaa.com
Conics
  Is there an error in this question or solution?
Chapter 5: Two Dimensional Analytical Geometry-II - Exercise 5.2 [Page 197]

APPEARS IN

Samacheer Kalvi Mathematics - Volume 1 and 2 [English] Class 12 TN Board
Chapter 5 Two Dimensional Analytical Geometry-II
Exercise 5.2 | Q 8. (iv) | Page 197

RELATED QUESTIONS

The parabola y2 = kx passes through the point (4, -2). Find its latus rectum and focus.


The double ordinate passing through the focus is:


The distance between directrix and focus of a parabola y2 = 4ax is:


Find the equation of the parabola in the cases given below:

Focus (4, 0) and directrix x = – 4


Find the equation of the ellipse in the cases given below:

Foci `(+- 3, 0), "e"+ 1/2`


Find the equation of the ellipse in the cases given below:

Length of latus rectum 8, eccentricity = `3/5` centre (0, 0) and major axis on x-axis


Find the equation of the ellipse in the cases given below:

Length of latus rectum 4, distance between foci `4sqrt(2)`, centre (0, 0) and major axis as y-axis


Find the equation of the hyperbola in the cases given below:

Centre (2, 1), one of the foci (8, 1) and corresponding directrix x = 4


Find the equation of the hyperbola in the cases given below:

Passing through (5, – 2) and length of the transverse axis along x-axis and of length 8 units


Find the vertex, focus, equation of directrix and length of the latus rectum of the following:

y2 = 16x


Find the vertex, focus, equation of directrix and length of the latus rectum of the following:

x2 = 24y


Find the vertex, focus, equation of directrix and length of the latus rectum of the following:

y2 = – 8x


Find the vertex, focus, equation of directrix and length of the latus rectum of the following:

x2 – 2x + 8y + 17 = 0


Find the vertex, focus, equation of directrix and length of the latus rectum of the following:

y2 – 4y – 8x + 12 = 0


Identify the type of conic and find centre, foci, vertices, and directrices of the following:

`x^2/25 + y^2/9` = 1


Identify the type of conic and find centre, foci, vertices, and directrices of the following:

18x2 + 12y2 – 144x + 48y + 120 = 0


Identify the type of conic and find centre, foci, vertices, and directrices of the following:

9x2 – y2 – 36x – 6y + 18 = 0


Choose the correct alternative:

The eccentricity of the hyperbola whose latus rectum is 8 and conjugate axis is equal to half the distance between the foci is


Choose the correct alternative:

If x + y = k is a normal to the parabola y2 = 12x, then the value of k is 14


Share
Notifications

Englishहिंदीमराठी


      Forgot password?
Use app×