Advertisements
Advertisements
Question
If -5 is a root of the quadratic equation `2x^2+px-15=0` and the quadratic equation `p(x^2+x)+k=0` 0has equal roots, find the value of k.
Solution
It is given that -5 is a root of the quadratic equation `2x^2+px-15=0`
∴ `2(-5)^2+pxx(-5)-15=0`
⇒ `-5p+35=0`
⇒` p=7`
The roots of the equation` px^2+px+k= 0=0` are equal.
∴ `D=0 `
⇒ `p^2-4pk=0`
⇒`(7)^2-4xx7xxk=0`
⇒`49-28k=0`
⇒` k=49/28=7/4`
Thus, the value of k is `7/4`
APPEARS IN
RELATED QUESTIONS
Write the discriminant of the following quadratic equations:
(x − 1) (2x − 1) = 0
Write the discriminant of the following quadratic equations:
x2 - x + 1 = 0
Find the value of k for which x = 1is a root of the equation `x^2+kx+3=0`
`2x^2+x-6=0`
`11-x=2x^2`
`3x^2-2x+2=0.b`
`x^2-(2b-1)x+(b^2-b-20)=0`
If 3 is a root of the quadratic equation` x^2-x+k=0` find the value of p so that the roots of the equation `x^2+2kx+(k^2+2k+p)=0` are equal.
Find the values of k for which the given quadratic equation has real and distinct root:
`5x^2-kx+1=0`
Find the discriminant of the quadratic equation 4x2 – 5 = 0 and hence comment on the nature of roots of the equation.