Advertisements
Advertisements
Question
Find the discriminant of the quadratic equation 4x2 – 5 = 0 and hence comment on the nature of roots of the equation.
Solution
4x2 – 5 = 0
Here a = 4, b = 0, c = –5
Discriminant (D) = b2 – 4ac
= 0 – 4 × 4(–5)
= 80 > 0
Since, D > 0, therefore roots are real and distinct.
APPEARS IN
RELATED QUESTIONS
` 2x^2-7x+6=0`
`sqrt3x^2-2sqrt2x-2sqrt3=0`
`x+1/x=3,x≠0`
`x^2-2ax-(4b^2-a^2)=0`
`x^2-(2b-1)x+(b^2-b-20)=0`
Find the nature of roots of the following quadratic equations:
`x^2-x+2=0`
If the roots of the quadratic equation `(c^2-ab)x^2-2(a^2-bc)x+(b^2-ac)=0` are real and equal, show that either a=0 or `(a^3+b^3+c^3=3abc)`
Find the value of p for which the quadratic equation `2x^2+px+8=0` has real roots.
Find the value of k for which the roots of `9x^2+8kx+16=0` are real and equal
Solve for x: \[\frac{16}{x} - 1 = \frac{15}{x + 1}, x \neq 0, - 1\]
