Advertisements
Advertisements
प्रश्न
Find the discriminant of the quadratic equation 4x2 – 5 = 0 and hence comment on the nature of roots of the equation.
उत्तर
4x2 – 5 = 0
Here a = 4, b = 0, c = –5
Discriminant (D) = b2 – 4ac
= 0 – 4 × 4(–5)
= 80 > 0
Since, D > 0, therefore roots are real and distinct.
APPEARS IN
संबंधित प्रश्न
In the following, determine whether the given quadratic equation have real roots and if so, find the roots:
x2 - 2x + 1 = 0
`2x^2+x-6=0`
`x^2-4x-1=0`
`x-1/x=3,x≠0`
`36x^2-12ax+(a^2-b^2)=0`
`x^2-4ax-b^2+4a^2=0`
`12abx^2-(9a^2-8b^2)x-6ab=0,` `Where a≠0 and b≠0`
Find the values of p for which the quadratic equation `(p+1)x^2-6(p+1)x+3(p+9)=0` `p≠-11`has equal roots. Hence find the roots of the equation.
If -5 is a root of the quadratic equation `2x^2+px-15=0` and the quadratic equation `p(x^2+x)+k=0` 0has equal roots, find the value of k.
Find the values of k for which the given quadratic equation has real and distinct roots:
`9x^2+3kx+4=0`