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प्रश्न
`2x^2+x-6=0`
उत्तर
We write, `x=4x-3x` as `2x^2xx(-6)=-12x^2=4xxx(-3x)`
`∴ 2x^2+x-6=0`
`⇒ 2x^2+4x-x-6=0 `
`⇒ 2x(x+2)-3(x+2)=0`
`⇒(x+2)(2x-3)=0`
`⇒x+2=0 or 2x-3=0`
`⇒x=-2 or x=3/2`
Hence, the roots of the given equation are `-2 and 3/2`
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