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Question
If A and B are mutually exclusive events, P(A) = 0.35 and P(B) = 0.45, find P(A ∩ B′)
Solution
Given that P(A) = 0.35 and P(B) = 0.45
Since the events A and B are mutually exclusive then P(A ∩ B) = 0
P(A ∩ B′) = P(A) – P(A ∩ B)
= 0.35 – 0
= 0.35
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