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Question
If S is the sample space and P(A) = \[\frac{1}{3}\] P(B) and S = A ∪ B, where A and B are two mutually exclusive events, then P (A) =
Options
1/4
1/2
3/4
3/8
Solution
1/4
Let P(B) = p
Then P(A) = \[\frac{1}{3}p\]
Since A and B are two mutually exclusive events, we have:
A ∪ B = S
⇒ P (A∪B) = P (S)
⇒ P (A∪B) = 1
⇒ P (A) + P (B) = 1
⇒ \[\frac{1}{3}p + p = 1\]
\[\Rightarrow \frac{4p}{3} = 1\]
\[ \Rightarrow p = \frac{3}{4}\]
∴ P (A) = \[\frac{1}{3}p = \frac{1}{3} \times \frac{3}{4} = \frac{1}{4}\]
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