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Question
If A and B are mutually exclusive events, P(A) = 0.35 and P(B) = 0.45, find P(A′ ∩ B′)
Solution
Given that P(A) = 0.35 and P(B) = 0.45
Since the events A and B are mutually exclusive then P(A ∩ B) = 0
P(A′ ∩ B′) = 1 – P(A ∪ B)
= 1 – 0.80
= 0.20
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