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If a→ is a unit vector perpendicular to b→ and (a→+2b→).(3a→-b→)=-5, find |b→|. - Mathematics

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Question

If `veca` is a unit vector perpendicular to `vecb` and `(veca + 2vecb).(3veca - vecb) = -5`, find `|vecb|`.

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Solution

As per question

`|veca| = 1`, `veca.vecb = 0`

∴ `(veca + 2vecb).(3veca - vecb) = -5`

`\implies 3|veca|^2 + 5(veca.vecb) - 2|vecb|^2 = -5`

`\implies 2|vecb|^2 = 8`

`\implies |vecb| = 2`

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