Advertisements
Advertisements
Question
If ∆ABC is similar to ∆DEF such that ∆DEF = 64 cm2 , DE = 5.1 cm and area of ∆ABC = 9 cm2 . Determine the area of AB
Solution
Since the ratio of areas of two similar triangles is equal to the ratio of the squares of any two corresponding sides.
`\therefore \text{ }\frac{Area\ (\Delta ABC)}{Area\,\,(\Delta DEF)}=(AB^2)/(DE^2)`
`\Rightarrow \frac{9}{64}=(AB^2)/(5.1)^2`
`\Rightarrow AB=\sqrt{3.65}`
⇒ AB = 1.912 cm
APPEARS IN
RELATED QUESTIONS
The areas of two similar triangles ∆ABC and ∆PQR are 25 cm2 and 49 cm2 respectively. If QR = 9.8 cm, find BC
In two similar triangles ABC and PQR, if their corresponding altitudes AD and PS are in the ratio 4 : 9, find the ratio of the areas of ∆ABC and ∆PQR
Prove that the area of the triangle BCE described on one side BC of a square ABCD as base is one half the area of the similar Triangle ACF described on the diagonal AC as base
D and E are points on the sides AB and AC respectively of a ∆ABC such that DE || BC and divides ∆ABC into two parts, equal in area. Find
If ΔABC and ΔBDE are equilateral triangles, where D is the mid-point of BC, find the ratio of areas of ΔABC and ΔBDE.
Areas of two similar triangles are 225 sq.cm. 81 sq.cm. If a side of the smaller triangle is 12 cm, then Find corresponding side of the bigger triangle.
∆ABC and ∆DEF are equilateral triangles. If A(∆ABC) : A(∆DEF) = 1 : 2 and AB = 4, find DE.
Ratio of areas of two similar triangles is 9 : 25. _______ is the ratio of their corresponding sides.
In a rectangle Length = 8 cm, Breadth = 6 cm. Then its diagonal = ______.
Use area theorem of similar triangles to prove congruency of two similar triangles with equal areas.