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Questions
If ∆ABC ~ ∆DEF such that area of ∆ABC is 16cm2 and the area of ∆DEF is 25cm2 and BC = 2.3 cm. Find the length of EF.
Triangles ABC and DEF are similar If area (∆ABC) = 16cm2, area (∆DEF) = 25 cm2 and BC = 2.3 cm, find EF.
Solution
We have,
`(Area(DeltaABC))/(Area(DeltaDEF))=(BC)^2/(EF)^2`
`\Rightarrow \frac{16}{25}=((2.3)^2)/(EF^2)`
`\Rightarrow EF=\sqrt{8.265}=2.875cm`
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