Advertisements
Advertisements
Question
Triangles ABC and DEF are similar If AB = 1.2 cm and DE = 1.4 cm, find the ratio of the areas of ΔABC and ΔDEF.
Solution
We have,
ΔABC ~ ΔDEF
AB = 1.2 cm and DF = 1.4 cm
By area of similar triangle theorem
`("Area"(triangleABC))/(Area(triangleDEF))="AB"^2/"DE"^2`
`=1.2^2/1.4^2`
`=1.44/1.96`
`=36/49`
APPEARS IN
RELATED QUESTIONS
The areas of two similar triangles ∆ABC and ∆PQR are 25 cm2 and 49 cm2 respectively. If QR = 9.8 cm, find BC
D, E, F are the mid-point of the sides BC, CA and AB respectively of a ∆ABC. Determine the ratio of the areas of ∆DEF and ∆ABC.
Diagonals of a trapezium ABCD with AB || DC intersect each other at the point O. If AB = 2CD, find the ratio of the areas of triangles AOB and COD.
Triangles ABC and DEF are similar If area (ΔABC) = 36 cm2, area (ΔDEF) = 64 cm2 and DE = 6.2 cm, find AB.
The areas of two similar triangles are 121 cm2 and 64 cm2 respectively. If the median of the first triangle is 12.1 cm, find the corresponding median of the other.
If ΔABC and ΔBDE are equilateral triangles, where D is the mid-point of BC, find the ratio of areas of ΔABC and ΔBDE.
∆ABC and ∆DEF are equilateral triangles. If A(∆ABC) : A(∆DEF) = 1 : 2 and AB = 4, find DE.
If ΔABC is similar to ΔDEF such that 2 AB = DE and BC = 8 cm then EF is equal to ______.
O is a point on side PQ of a APQR such that PO = QO = RO, then ______.
If ΔABC ∼ ∆PQR and AB : PQ = 2 : 3, then find the value of `(A(triangleABC))/(A(trianglePQR))`.
