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If aijka→=i^+j^+k^ and cjkc→=j^-k^. find a vector bb→ satisfying abca→×b→=c→ and aba→·b→ = 3. - Mathematics and Statistics

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Question

If `vec"a" = hat"i" + hat"j" + hat"k"` and `vec"c" = hat"j" - hat"k"`. find a vector `vec"b"` satisfying `vec"a" xx vec"b" = vec"c"` and `vec"a"·vec"b"` = 3.

Sum

Solution

Given,  `vec"a" = hat"i" + hat"j" + hat"k"`, `vec"c" = hat"j" - hat"k"`

Let `vec"b" = "x"hat"i"+"y"hat"j"+"z"hat"k"`

Then `vec"a"·vec"b"` = 3 gives

`(hat"i" + hat"j" + hat"k"). ("x"hat"i"+"y"hat"j"+"z"hat"k")`= 3

:. (1)(x) + (1)(y) + (1)(z) = 3

Also, x + y + z = 3    ...(1)

Also, `vec"c" = hat"a"xxhat"b"`

`hat"j" - hat"k" = |(hat"i", hat"j", hat"k"),(1, 1, 1),("x", "y", "z")|`

= (z - y)`hat"i"` - (z - x)`hat"j"` + (y - x)`hat"k"`

= (z - y)`hat"i"` + (x - z)`hat"j"` + (y - x)`hat"k"`

By equality of vectors,

z - y = 0      ...(2)

x - z = 1     ...(3)

y - x = - 1   ...(4)

From (2), y = z

From (3), x = 1 + z

Substituting these values of x and y in (1), we get

1 + z + z + z = 3

`"z" = 2/3`

y = z = `2/3`

x = 1 + z = 1 + `2/3` = `5/3`

`vec"b" 5/3hat"i" + 2/3hat"j" +2/3hat"k"`

i.e,   `vec"b" = 1/3(5hat"i" + 2hat"j" + 2hat"k")`

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Vector Product of Vectors (Cross)
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