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If c is r.m.s. speed of molecules in a gas and v is the speed of sound waves in the gas, show that c/v is constant and independent of temperature for all diatomic gases. - Physics

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Question

If c is r.m.s. speed of molecules in a gas and v is the speed of sound waves in the gas, show that c/v is constant and independent of temperature for all diatomic gases.

Numerical

Solution

We know that for molecules, c = `sqrt((3P)/P)`.

We know that `p/ρ = (PT)/M`. Therefore, we get

⇒ `p/ρ = ((RT)/V)/(M/V)`

⇒ `p/ρ = (RT)/M`

Thus, we can write the equation for the molecules as,

⇒ c = `sqrt((3RT)/M)`

Where M is the molar mass of gas.

For sound waves, we have

⇒ v = `sqrt((ϒP)/ρ)`

We know that PV = nRT. For n = 1, we have

⇒ P = `(RT)/V`

Thus, we get ⇒ v =  `sqrt((ϒRT)/M)`

⇒ `c/v = sqrt((3RT)/M)/(sqrt((ϒRT)/M)`

⇒ `c/v = sqrt(3/ϒ)`

We know that ϒ = `C_P/C_v = 7/5` is an adiabatic constant for diatomic gas. Therefore, we get

⇒ `c/v = sqrt(3/(7/5)`

⇒ `c/v = sqrt((3 xx 5)/7`

⇒ `c/v = sqrt(15/7)` = constant.

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The Speed of a Travelling Wave
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Chapter 15: Waves - Exercises [Page 112]

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NCERT Exemplar Physics [English] Class 11
Chapter 15 Waves
Exercises | Q 15.33 | Page 112

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