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Question
If the line y = \[\sqrt{3}\] x + k touches the circle x2 + y2 = 16, then find the value of k.
Solution
The centre and the radius of the circle x2 + y2 = 16 are (0, 0) and 4
Now, the perpendicular distance from the centre of the circle to the tangent y = \[\sqrt{3}\] x + k is equal to the radius of the circle
\[ \Rightarrow \pm 4 = \frac{k}{2}\]
\[ \Rightarrow k = \pm 8\]
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