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Question
If the points P (x, y) is equidistant from A (5, 1) and B (−1, 5), then
Options
5x = y
x = 5y
3x = 2y
2x = 3y
Solution
It is given that P (x , y) is equidistant to the point `A (5,1) " and " B (-1 , 5)`
So,
`PA^2 = PB^2`
So apply distance formula to get the co-ordinates of the unknown value as,
`(x - 5)^2 + (y - 1)^2 = (x +1)^2 + (y-5)^2`
On further simplification we get,
25-10x + 1 - 2y = 1 +2x + 25 - 10y
So,
12x = 8y
Thus,
3x = 2y
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