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Question
If the distance between the points (4, p) and (1, 0) is 5, then p =
Options
± 4
4
−4
0
Solution
It is given that distance between P (4, p) and Q(1, 0) is 5.
In general, the distance between A(x1,y1) and B(x2 , y2) is given by,
`AB^2 = (x_2-x_1)^2 + (y_2-y_1)^2`
So,
`5^2 = (4-1)^2+(p-0)^2`
On further simplification,
`p^2 = 16`
`p = +-4`
So,
`p = +-4`
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