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Question
In a cyclotron, magnetic field of 3·5Wb/m2 is used to accelerate protons. What should be the time interval in which the electric field between the Dees be reversed?
(Mass of proton = 1· 67 x 10-27Kg, Charge on proton =1·6x10-19c).
Solution
B = 3.5 Wb/m2 , mP = 1.67 × 10-27 Kg,
e = 1.6 × 10-19 C,
t = ?
t = `pi"m"_"P"/"Bq"_"p"`
t = `(3.142 xx 1.67 xx 10^-27)/(3.5 xx 1.6 xx 10^-19)`
`= (3.142 xx 1.67)/(3.5 xx 1.6) xx 10^-8`
= [log (3.142) + log (1.67) - log (3.5) - log (1.6)] × 10-8
= [0.4972 + 0.2227 - 0.5441 - 0.2041] × 10-8
= [antilog (- 0.0283)] × 10-8 s
= 0.9369 × 10-8 s
= 9.369 × 10-9 s
The dees should be reversed within time interval of 9.369 × 10-9 S.
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