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Question
In figure, points A, B, C, D and E are collinear such that AB = BC = CD = DE. Then 
Mid point of AE is ______
Solution
In figure, points A, B, C, D and E are collinear such that AB = BC = CD = DE. Then
Midpoint of AE is C
Explanation:
∵ AB + BC = CD + DE
⇒ AC = CE
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