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Question
In quadrilateral ABCD, side AB is the longest and side DC is the shortest.
Prove that: D > B.
Solution
∠5 > ∠6 [ AB > AD ]
∠3 > ∠8 [ BC > CD ]
∴ ∠5 + ∠3 > ∠6 + ∠8
⇒ ∠D > ∠B
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