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Question
In the adjoining figure, circle with center D touches the sides of ∠ACB at A and B. If ∠ACB = 52°, find measure of ∠ADB.
Solution
∴ ∠ACB + ∠CAD + ∠CBD + ∠ADB = 360° ......[The sum of all angles of a quadrilateral is 360°]
∴ 52° + 90° + 90° + ∠ADB = 360° ......[Tangent theorem]
∴ ∠ADB + 232° = 360°
∴ ∠ADB = 360° – 232°
∴ ∠ADB = 128°
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