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Question
In the adjoining figure, write
(i) The coordinates of A, B and C.
(ii) The equation of the line through A and | | to BC.
Solution
(i) A = (2, 3), B = (-1, 2), C = (3, 0).
(ii) Slope of BC = `(y_2 - y_1)/(x_2 - x_1) = (2 - 0)/(-1 - 3) = (2)/(-4)`
m1 = `(-1)/(2)`
Since lines are parallel
∴ m1 = m2
Hence, m2 = `-(1)/(2)`
and passing through point (2, 3)
∵ Equation of line is y - y1 = m2 (x - x1)
∴ required line is y - 3 = `(-1)/(2)(x - 2)`
2y - 6 = -x + 2
x + 2y = 8.
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