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Question
In the below fig, AB || CD || EF and GH || KL. Find `∠`HKL
Solution
Produce LK to meet GF at N.
Now, alternative angles are equal
`∠`CHG = `∠`HGN = 60°
`∠`HGN = `∠`KNF = 60° [Corresponding angles]
∴`∠`KNG = 180° - 60° = 120°
`∠`GNK = `∠`AKL = 120° [Corresponding angles]
`∠`AKH = `∠`KHD = 25° [Alternative angles]
∴`∠`HKL = `∠`AKH + `∠`AKL = 25° +120° = 145°.
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