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Question
In the given figure, AB and DE are perpendiculars to BC.
Prove that : ΔABC ~ ΔDEC
Solution
In ΔABC and ΔDEC,
∠ABC = ∠DEC ...(both are right angles)
∠ACB = ∠DCE ....(common angles)
ΔABC ∼ ΔDEC ...(AA criterion for similarity)
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