Advertisements
Advertisements
Question
In the given figure find the value of x
Solution
For ∆LNM, ∠LMK is the exterior angle at M
Exterior angle = sum of opposite interior angles
∠LMK = ∠MLN + ∠LNM
= 26° + 30°
= 56°
∠JMK = 56° ...[∵ ∠LMK = ∠JMK]
x is the exterior angle at J for ∆JKM
∴ x = ∠JKM + ∠KMJ ...[∵ Sum of interior opposite angles]
x = 58° + 56° ...[∵ ∠JMK = 56°]
x = 114°
APPEARS IN
RELATED QUESTIONS
Find the value of the unknown exterior angle x in the following diagram:
Find the value of the unknown interior angle x in the following figure.
∠ACD is an exterior angle of ∆ABC. The measures of ∠A and ∠B are equal. If m∠ACD = 140°, find the measures of the angles ∠A and ∠B.
Using the diagram find the value of x.
In ∆JKL, if ∠J = 60° and ∠K = 40°, then find the value of exterior angle formed by extending the side KL
If the exterior angle of a triangle is 130° and its interior opposite angles are equal, then measure of each interior opposite angle is ______.
In the given figure QP || RT. Find the values of x and y.
Find the measure of ∠A in the given figure.
If the sides of a triangle are produced in an order, show that the sum of the exterior angles so formed is 360°.
In the given figure, ∆PQR is right-angled at P. U and T are the points on line QRF. If OP || ST and US || RP, find ∠S.