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Maharashtra State BoardSSC (English Medium) 9th Standard

In the given figure, □PQRS and □ABCR are two parallelograms. If ∠P = 110° then find the measures of all angles of □ABCR. - Geometry

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Question

In the given figure, `square`PQRS and `square`ABCR are two parallelograms. If ∠P = 110° then find the measures of all angles of `square`ABCR.

Sum

Solution

`square`PQRS is a parallelogram.     ...[Given]

∴ ∠R = ∠P    ...[Opposite angles of a parallelogram]

∴ ∠R = 110°   ...(i)

`square`ABCR is a parallelogram.     ...[Given]

∴ ∠A + ∠R = 180°      ...[Adjacent angles of a parallelogram are supplementary]

∴ ∠A + 110° = 180°    ...[From (i)]

∴ ∠A = 180° - 110°

∴ ∠A = 70°

∴ ∠C = ∠A = 70°

∴ ∠B = ∠R = 110°      ...[Opposite angles of a parallelogram]

∴ ∠A = 70°, ∠B = 110°,

∴ ∠C = 70°, ∠R = 110°

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Chapter 5: Quadrilaterals - Practice Set 5.1 [Page 62]

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Balbharati Geometry (Mathematics 2) [English] 9 Standard Maharashtra State Board
Chapter 5 Quadrilaterals
Practice Set 5.1 | Q 6 | Page 62
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