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Question
In what ratio is the line joining (2, -4) and (-3, 6) divided by the line y = O ?
Solution
Let P (x, O) be tne point on line y = 0 i.e. x-axis which divides the line segment AB in the ratio k : 1.
Coordinates of P are
x = `(3 "k" + 2)/("k + 1")` , 0 = `(6"k" - 4)/("k + 1")`
⇒ 6k = 4
⇒ k = `2/3`
Hence tne required ratio is 2: 3.
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Activity:
∴ By section formula,
∴ x = `("m"x_2 + "n"x_1)/square`,
∴ x = `(3 xx 8 + 1 xx 4)/(3 + 1)`,
= `(square + 4)/4`,
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