Advertisements
Advertisements
Question
In Δ XYZ, XY = 4 cm, YZ = 6 cm, XZ = 5 cm, If ΔXYZ ~ ΔPQR and PQ = 8 cm then find the lengths of remaining sides of ΔPQR.
Solution
Consider, ΔXYZ ~ ΔPQR
`therefore ("XY")/("PQ") = ("YZ")/("QR") = ("XZ")/("PR")` ...[Corresponding sides of similar triangles]
⇒ `4/8 = 6/("QR") = 5/("PR")`
⇒ `4/8 = 6/("QR")`
⇒ `"QR" = (8 xx6)/4`
⇒ QR = 12 cm
⇒ `4/8 = 5/("PR")`
⇒ PR = `(8 xx5)/4`
⇒ PR = 10 cm
Hence, the lengths of remaining sides of ΔPQR are 12 and 10 cm.
APPEARS IN
RELATED QUESTIONS
ΔDEF ~ ΔMNK. If DE = 5, MN = 6, then find the value of `"A(ΔDEF)"/"A(ΔMNK)"`
In the following figure, AP ⊥ BC, AD || BC, then find A(∆ABC) : A(∆BCD).
Select the correct alternative answer and write it.
The ratio of corresponding sides of similar triangles is 5 : 7, then what is
the ratio of their areas ?
(A)25 : 49 (B) 49 : 25 (C) 5 : 7 (D) 7 : 5
In the given figure, CB ⊥ AB, DA ⊥ AB.
if BC = 4, AD = 8 then `(A(Δ ABC))/(A(Δ ADB))` find.
In the adjoining figure,
PQ ⊥ BC, AD ⊥ BC,
PQ = 4, AD = 6
Write down the following ratios.
(i)`(A(ΔPQB))/(A(ΔADB))`
(ii)`(A(ΔPBC))/(A(ΔABC))`
With the help of the information given in the figure, fill in the boxes to find AB and BC .
AB = BC (Given)
∴∠ BAC = ∠ BCA =
∴ AB = BC = × AC
= × `sqrt8`
= × `2sqrt2`
= 2
Prove that an equilateral triangle is equiangular.
If ΔXYZ ~ ΔLMN, write the corresponding angles of the two triangles and also write the ratios of corresponding sides.
Draw a sketch of a pair of similar triangles. Label them. Show their corresponding angles by the same signs. Show the lengths of corresponding sides by numbers in proportion.
In the following figure, state whether the triangles are similar. Give reason.