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Question
Let `A = [(2,1),(0,-2)], B = [(4,1),(-3,-2)] and C = [(-3,2),(-1,4)]`. Find `A^2 + AC - 5B`
Solution
Given,
`A = [(2,1),(0,-2)], B = [(4,1),(-3,-2)] , C = [(-3,2),(-1,4)]`
Thus
`A^2 = [(2,1),(0,-2)][(2,1),(0,-2)] = [(4+0,2-2),(0+0,0+4)] = [(4,0),(0,4)]`
`AC = [(2,1),(0,-2)][(-3,2),(-1,4)] = [(-6-1,4+4),(0+2, 0-8)] = [(-7,8),(2,-8)]`
`5B = 5[(4,1),(-3,-2)] = [(20, 5),(-15,-10)]`
`:. A^2 + AC - 5B = [(4,0),(0,4)] + [(-7,8),(2,-8)] - [(20,5),(-15,-10)] = [(-23,3),(17,6)]`
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