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Question
Let f(x) = x5 + 2x – 3 find (f−1)'(-3)
Solution
f(x) = x5 + 2x – 3
Differentiating w.r.t. x, we get
f'(x) = 5x4 + 2
At y = – 3, x = 0
∴ (f−1)'(-3) = `1/("f'"(0))`
= `1/(5(0)^4 + 2)`
= `1/2`
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