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Question
Make I the subject of the following M = `"L" /"F"(1/2"N" - "C") xx "I"`. Find I, If M = 44, L = 20, F = 15, N = 50 and C = 13.
Solution
M = `"L" /"F"(1/2"N" - "C") xx "I"`
⇒ M - L = `(1)/"F"(1/2"N" - "C") xx "I"`
⇒ F(M - L) = `(1/2"N" - "C") xx "I"`
⇒ F(M - L) = `(("N" - 2"C")/2) xx "I"`
⇒ `(2"F"("M" - "L"))/(("N" - 2"C")) = "I"`
Substituting the values of M = 44, L = 0, F = 15, N = 50 and C = 30, we get
I = `(2"F"("M" - "L"))/(("N" - 2"C")`
= `(2 xx 15(44 - 20))/(50 - 2 xx 13)`
= `(30 xx 24)/(24)`
= 30.
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