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Match the items of column I with items of column II. Column I Column II (i) Methanol (a) Conversion of phenol to o-hydroxysalicylic acid (ii) Kolbe’s reaction (b) Ethyl alcohol (iii) Will - Chemistry

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Question

Match the items of column I with items of column II.

  Column I Column II
(i) Methanol (a) Conversion of phenol to o-hydroxysalicylic acid
(ii) Kolbe’s reaction (b) Ethyl alcohol
(iii) Williamson’s synthesis (c) Conversion of phenol to salicylaldehyde
(iv) Conversion of 2° alcohol to ketone (d) Wood spirit
(v) Reimer-Tiemann reaction (e) Heated copper at 573 K
(vi) Fermentation (f) Reaction of alkyl halide with sodium alkoxide
Match the Columns

Solution

  Column I Column II
(i) Methanol (d) Wood spirit
(ii) Kolbe’s reaction (a) Conversion of phenol to o-hydroxysalicylic acid
(iii) Williamson’s synthesis (f) Reaction of alkyl halide with sodium alkoxide
(iv) Conversion of 2° alcohol to ketone (e) Heated copper at 573 K
(v) Reimer-Tiemann reaction (c) Conversion of phenol to salicylaldehyde
(vi) Fermentation (b) Ethyl alcohol

Explanation:

(i) Methanol is also known as ‘wood spirit’ as it was produced by the destructive distillation of wood.

(ii) In Kolbe’s reaction, 2-hydroxybenzoic acid (salicylic acid) is prepared by the reaction of phenol with CO2 gas.

(iii) Williamson's synthesis is an important method for the preparation of either. In this method, an alkyl halide is allowed to react with sodium alkoxide.

\[\ce{R - X + R' -  \overset{-}{\overset{\bullet\bullet}{\underset{\bullet\bullet}{O}}} \overset{+}{N}a -> R - \overset{\bullet\bullet}{\underset{\bullet\bullet}{O}} - R' + NaX}\]

(iv) When a 2° alcohol is allowed to pass overheated copper at 573 K, dehydrogenation takes place and an ketone is formed.

\[\begin{array}{cc}
\ce{R - CH - R' ->[Cu][573 K] R - C - R'}\\
|\phantom{...................}||\phantom{.}\\
\phantom{.}\ce{OH}\phantom{.................}\ce{O}\phantom{..}
\end{array}\]

(v) On treating phenol with chloroform in the presence of \[\ce{NaOH}\], an aldehydic group is introduced at ortho position of benzene ring

(vi) Ethanol is prepared by the fermentation of sugars.

\[\ce{C12H22O11 + H2O ->[Invertase] C6H12O6 + C6H12O6}\]

\[\ce{C6H12O6 ->[Zymase] 2C2H5OH + 2CO2}\]

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Chapter 11: Alcohols, Phenols and Ethers - Multiple Choice Questions (Type - I) [Page 162]

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NCERT Exemplar Chemistry [English] Class 12
Chapter 11 Alcohols, Phenols and Ethers
Multiple Choice Questions (Type - I) | Q 60 | Page 162
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